Chem.ch7.exam3

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xiongav
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114367
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Chem.ch7.exam3
Updated:
2011-11-04 02:15:44
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Chemical Reactions
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Chem.ch7.exam3
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  1. Classifying Chemical Reactions.

    Synthesis
    Decomposition
    Single Displacement
    Double-Displacement
    Synthesis: (A + B --> AB); 2 H2 + O2 --> 2 H2O

    Decomposition: (AB --> A + B); 2NaN3 --> 2 Na + 3 N2

    • Single-displacement: (A + BC --> AC + B)
    • Zn(s) + CuSO4(aq) --> Cu(s) + ZnSO4(aq)

    • Double-displacement: (AB + CD --> AD + CB)
    • Pb(NO3)2(aq) + 2 KI(aq) --> PbI2(s) + 2 KNO3(aq)
  2. Specific types of reactions.

    Precipitation
    Acid-base
    Gas evolution
    Redox
    Combustion
    Precip: a solid or precip. forms upon mixing two (aq) solutions.

    Acid-Base: Water forms upon mixing an acid and a base.

    Gas evo: A gas forms upon mixing two (aq) solutions.

    Redox: e- are transferred from one substance to another.

    Combustion: A substance reacts w/ O2, emitting heat, and forming an oxygen-containing compound and, in many cases, water.
  3. Mass-->Mass Conversions (example)

    How many grams of sodium oxide can be synthesized from 17.4 g of sodium? Assume that more than enough oxygen is present. The balanced equation is:

    4 Na(s) + O2(g) --> 2 Na2O(s)
    • Given: 17. g Nan
    • Find: g Na2O

    17.4 g Na x 1 mol Na/22.99 g Na (x) 2 mol Na2O/4 mol Na (x) 61.98 g Na2O/1 mol Na2O =

    23.5 g Na2O
  4. Mole-toMole Conversions (example)

    How many moles of sodium oxide can be synthesized from 4.8 mol of sodium? Assume that more than enough O2 is present. The balanced equation is:

    4 Na(s) + O2(g) --> 2 Na2O(s)
    • Given: 4.8 mol Na
    • Find: mol Na2O

    4.8 mol Na x 2 mol Na2O / 4 mol Na =

    2.6 mol Na2O
  5. What is the mass-to-mass conversion?
    grams (x) <--> moles (x) <--> moles (y)<--> grams (y)

    between g (x) and mol (x): molar mass of (x)

    between mol (x) and mol (y): MOLE RATIO from balanced equation.

    between mol (y) and g (y): molar mass of (y)

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