# Calculus 3 exam 1

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1. Question 1 Consider the three points P1=(1,1,1), P2=(2,0,1) and P3=(1,2,3)
A. Find the vectors P1P2 and P1P3?
• P1P2 = P2-P1 = (2,0,1) - (1,1,1) = (1,-1,0)
• P1P3 = P3-P1 = (1,2,3) - (1,1,1) = (0,1,2)
2. Question 1 Consider the three points P1=(1,1,1), P2=(2,0,1) and P3=(1,2,3)
B. Find the cross product P1P2 X P1P3 (computation details required)
• ( i j k )
• (1 -1 0) = (-2 + 0) i + (2+0) j + (0+1) k = -2i + 2j + k
• ( 0 1 2 )
3. Question 1 Consider the three points P1=(1,1,1), P2=(2,0,1) and P3=(1,2,3)
C. Find the area of the triangle P1P2P3 formed by these three points by the formula 1/2 ||P1P2 X P1P3|| =
• P1P2 X P1P3= -2i + 2j + k
• use the formula
• 1/2 || -2i + 2j + k ||
• = square root (

## Card Set Information

 Author: edulalo999 ID: 122350 Filename: Calculus 3 exam 1 Updated: 2011-12-10 04:47:57 Tags: calc Folders: Description: exam 1 Show Answers:

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