Two wells are located 100 feet apart in a sand aquifer with a hydraulic conductivity of 0.04 feet per day. The head of well 1 is 96 feet and the head of well 2 is 99 feet.
What is the horizontal hydraulic gradient between the wells?
- [(head 2 - head 1) / L
- [(99-96) / (100)] = 3/100 or 0.03
What is the velocity of water between the two wells?
- V= (K) (dh / dl)
- V= (0.04 ft/d) (0.03)=0.0012 ft/d
Velocity is a speed…so its distance divided by time…milesperhour