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Convert degree to radians
Degree oover one times Pie over one

Radians to degree
Radians times 180 over pie

Find measurements of triangle
a squared plus b squared equals c squared

Sin:
Cos:
Tan:
CSc;
Sec:
Cot:
 sin: 0/h
 Cos: A/h
 Tan: O/a
 Csc: H/o
 sec: h/a
 Tan: a/o

csc Theda: negative squareroot three
negative square root of 3, negative one, square root two triangle

Terminal side of angle A stand post. goes through point (7,24) find six trig. function..
mark point on graph..make into triangle...theda is always in middle

Find Exact Value of each Expression
Sin14pie
3
1st. break the unit circle up into 3 regions..then count around it until you get to 14...at that point tell what the sine is...It will be the second point given..(y)

Find Amp, period, phase shift..
y=4cos(3x2pie)
 Amp: 4
 Period: 2(pie)/3 >2pie/B
 Ps: 2pie/3 > c/b
 always Minus in formula!!

Find Exact falue of trigonomic function:
Tan (pie/8)
 Tan(pie/4)/2) ( two times whatever number gives you..the begining number. then put it into formula
 Find places on unit circle and use the sine and cosine points to put into the formula..then just simply
 add demoinators when

Find exact of the folowing then given you sine A= whatevr with lessthan or greater then signs
basically you use whats given to make a triangel the woce you do that you do like what you did before...then looks for formula on formula part of unit circle can be double identity or sum and difference depending of if your multiplyeing (double) or adding (sum

Solve each equation on the interval (o, 2pie)
tanx= neg square root of three
First it is ov. that its over one...So make a triagle out of this where tan= o/a...so the opp sign of theda needs to be neg squarroot 3 and age. needs to be neg 1 bc thats obvly a squr. 3, 1, square twoo trig. then find sin and cos of them and the points that both share the same sign and cos are the answers... neg and pos. so shlould be two answers

Find Arc
 S=RTheda
 s:length
 R: radius
 theda: angle in radians

Solving triangles:
side 'c'/SinC = b/sinB

Polar cordinates to rectangular cordinates
 (2, 5pie/3)
 2=r
 5pie/3=Theda
 1. x=rcostheda
 y=rsintheda

Convert to a polar equation:
rSINEtheda= whatever is given as y

Convert to rectangular equation:
 r= 8 so...
 x2+y2=8^2
 x2+y2=64

Vector form of (5,6) q: (3,12)


Find Mag or {V} of <5,6>
 (5)^2+(6)^2 then take square root...
 answer is square root of 61

Unit vector in same direction as V
V/{v} (5/squaroot 61,6/squareroot/61)

