genchem exam 1 ch 1 review
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x ft in 1 mile
5280 ft in 1 mile

x km in 1 mile
1.609 km in 1 mile

x cm in 1 inch
2.54 cm in 1 inch















Hydrogen BiCarbonate
HCO3





Hydrogen Phosphate
HPO4 2

Dihydrogen phosphate
H2PO4





VF3
Vanadium(III)Fluoride



Alkali Metals
 Lithium
 Sodium
 Potassium
 Rubidium
 Cesium
 Francium

Alkali Earth Metals
 Beryllium
 Magnesium
 Calcium
 Strontium
 Barium
 Radium

Molarity
Moles of Solution/Liters

Fractional Abundance
Substance1x + (1x)substance2 = average

F to C
substract 32, multiply by 5/9

C to F
Multiply by 9/5, Add 32


Mass of Composition in Sample 2
(Mass of Composition in Sample1/Mass of Sample 1) * Mass of Sample 2

What was the percent yield?
 1. find out moles A
 2. find atomic/molecular mass of target
 3. consider molar ratio
 4. multiply moles * molecular mass
 Gives theoretical yield

Limiting Reactant Problems
 Convert g reactants to moles
 Consider molar ratio between reactants
 Consider molar ratio between limiting and product
 Multiply/Divide if necessary

Neutralization
 Convert target that was neutralized to moles (divide by molar mass)
 Consider mole ratio between target and neutralizer
 Multiply/Divide if necessary
 Divide by volume given