In the following electron configuration, what is the value of n, what is the number of valence electrons, and what is the number of core electrons? O: 1s22s22p4
Highest coefficient number is 2, so n = 2. There are 2 of them, so adding their exponents together gives the number of valence electrons:
2 + 4 = 6 valence electrons.
To find core electrons, add up the exponents of the rest of the configuration, so in this case, 2 core electrons from 1s2.