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Multiplying monomials.
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Multiplying monomials.
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Multiplying monomials.
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Multiplying a Monomial by a Polynomial.

Multiplying a Monomial by a Polynomial.

Multiplying Binomials.

Multiplying Binomials.

Multiplying a binomial by a trinomial.
*Each term in the first polynomial must be multiplied by each term in the second.
x(5x2)+x(2x)+x(6)+4(5x2)+4(2x)+4(6)
5x ^{3}2x^{2}6x+20x^{2}8x24

Formula for "Special Case Products"
The product of congugates results in a ______ of ________.
The square of a binomial results in a _______ _______ trinomial.
 difference
 squares
 perfect
 square

Special Case Formula #1:
a ^{2} ab + ab b ^{2 }
(difference of squares)

Special Case Formula #2:
 (a+b)(a+b)
 a^{2}+ab+ab+b^{2}
(perfect square trinomial)

The product of conjugates results in a ______ of _______.
 difference
 squares

The square of a binomial results in a _______ _______ trinomial.
 perfect
 square

Find a polynomial that represents the volume of the cube:
V= (x+4)(x+4)(x+4)
Step 1: Multiplying from left to right, you notice that you're squaring a binomial. So, you'll get a perfect square trinomial.
 Step 2: Rewrite the equation:

Step 3: Multiply each term in first parentheses by each term in the 2nd.
x ^{2}*x+x ^{2}*4+8x*x+8x*4+16*x+16*4
x ^{3} + 4x^{2} + 8x^{2} + 32x + 16x + 64
Step 4: Combine like terms:
V =

Multiplying Conjugates.
Once you recognize the conjugate, you know you will end up with a difference in squares, so you don't have to multiply the "long way".

Multiplying Conjugates.
Once you recognize the conjugate, you know you will end up with a difference in squares, so you don't have to multiply the "long way".

Squaring Binomials.
We know that the result will be a perfect square trinomial. So, you don't have to multiply (a+b)(a+b) the long way.
(2x) ^{2} + 2(2x)(5) + (5) ^{2}
 SAME AS:

Squaring Binomials.
We know that the result will be a perfect square trinomial. So, you don't have to multiply (a+b)(ab) the long way. Just remember to put the negative sign in front of the middle term.
(3y ^{2}) ^{2}  2(3y^{2})(7w) + (7w) ^{2}

