Given the following reaction:
4 KO_{2} + 2 H_{2}O + 4 CO_{2} ==> 4 KHCO_{3} + 3 O_{2}
How many moles of O_{2} will be produced if 3.09 moles of CO_{2} react completely?
2.32 moles of O_{2
}
Given the same reaction as before:
4 KO_{2} + 2 H_{2}O + 4 CO_{2} ==> 4 KHCO_{3} + 3 O_{2}
Great! 2.32 moles of O_{2} were produced.
Now, How many molecules of O_{2} does this number of moles represent?
It represents 1.40e24 molecules of O_{2}_{}
Given the same reaction as before:
4 KO_{2} + 2 H_{2}O + 4 CO_{2} ==> 4 KHCO_{3} + 3 O_{2}
Great job! 1.40e24 molecules is correct.
Now, How many grams of O_{2} does 2.32 moles represent?
It makes 74.2 grams of O_{2}
What do Atoms, Formula Units, and Molecules have in common?
They are all part of the particle family and always use the this 6.022*10^{23 }when trying to calculate the atom, formula unit, and molecule of and element
From going to a mole of an element to the mass of that same element what equation do you use?
You use 1molX= ?g of X
X= periodic table mass
To go from atom to mass you use...
x*10^{-n }grams
x=number multiplied by 10^{-n
}n= the number that 10 is powered by
When going from 1 mole of a element to the particle of an element what equation do you use?
You use...
1mol of X=6.022*10^{23}
(BIG) (Tiny)
When using Stoichiometry what is the process?
First you start from Old Mass Island to Old Mole Island and pay a toll of 1 so that you the Molar Mass of something. Then you go from Old Mole Island to New Mole Island by using the molar ratio of two elements. The you go from New Mole Island to New Mass Island to figure out the molar mass of the new element.
Periodic table formula is...
?g of X= 6.022*10^{23} part of X
How calculate on the inspire..
example: 64*6.022EE23/18.02enter
What is the Equivalent of a mole?
It is equivalent to a handful of a grain of sand.
How do you find the number moles there are in 75.0 grams of Zn?
?mol of Zn= 75.0 grams of Zn * 1mol of Zn
1 65.39gramsZn
=1.15 mol of Zn
How do you find the number of moles there are in 6.32*10^{23} of Cu?