Phys1 - Motion
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- 1 gigameter (G) = 109 m
- 1 megameter (M) = 106 m
- 1 kilometer (km) = 103 m
- 1 centimeter (cm) = 10-2 m
- 1 millimeter (mm) = 10-3 m
- 1 micrometer (µm) = 10-6 m
- 1 nanometer (nm) = 10-9 m
- 1 Ångström (Å) = 10-10 m
- 1 picometer (pm) = 10-12 m
- 1 femptometer (fm) = 10-15 m
- √2 = 1.4
- √3 = 1.7
- sin30 = 1/2
- cos30 = √3/2 ~ .86
- sin60 = √3/2
- cos60 = 1/2
- sin & cos 45 = √2/2 ~ .7
1 mg = 10-3 g = 10-6 kg
- a Scalar quantity that refers to how much ground an object has covered during its motion
- will only equal 0 if you don’t move at all
- a Vector quantity that refers to how far out of place an object is from where it started, aka it’s the object's overall change in position
- displacement is the quantity that can equal 0 when you end in the same place you started
- change in velocity divided by the elapsed time for that change
- a = v2 - v1 / Δt
- aka change in velocity / elapsed time
Most basic translational motion equation:
- d = vt
- distance (meters) = velocity (m/s) * time (s)
What equation should be used if vf is missing?
d = vot + 1/2at2
What equation should be used if d is missing?
vf = vo + at
What equation should be used if t is missing?
vf2 = vo2 + 2ad
Equation to find the time at the top of a projectile motion problem?
- ttop = voy/g
- same thing as saying m/s * s2/m
Equation to find the height at the top of a projectile motion problem?
h = voy2 / 2g
What equation can be used to determine an object’s displacement during FREE-FALL?
- d (Δh) = 5t2
- from d = vot + 1/2at2
Objects with a ____ contact area-to-mass ratio experience a more significant impact of wind resistance than their denser counterparts.
Objects with a LARGE surface area : mass ratio experience MORE wind resistance than their denser (therefore heavier) counterparts
• vterm occurs when the drag Force upward is equal & opposite to the Force of gravity (Fg
- • the object with the greatest terminal velocity will be:
- 1. the DENSEST
2. have the LEAST amount of contact area
Range Equations (3)
- r = vo2sin2θ / g
- r = 2voxvoy / g
- r45° = 4hmax
Which launch angle results in the maximum range & which results in the maximum height?
• a 45° launch angle corresponds to the maximum possible RANGE
• a 90° launch angle corresponds to the maximum possible HEIGHT
• 30° & 60° launch angles correspond to the same range
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