Phys1 - Motion

Card Set Information

Author:
mse263
ID:
285169
Filename:
Phys1 - Motion
Updated:
2014-10-07 19:56:09
Tags:
Physics
Folders:
Physics
Description:
Chapter 1
Show Answers:

Home > Flashcards > Print Preview

The flashcards below were created by user mse263 on FreezingBlue Flashcards. What would you like to do?


  1. Meter Conversions
    • 1 gigameter (G) = 109 m
    • 1 megameter (M) = 106 m
    • 1 kilometer (km) = 103 m
    • 1 centimeter (cm) = 10-2 m
    • 1 millimeter (mm) = 10-3 m
    • 1 micrometer (µm) = 10-6 m
    • 1 nanometer (nm) = 10-9 m
    • 1 Ångström (Å) = 10-10 m
    • 1 picometer (pm) = 10-12 m
    • 1 femptometer (fm) = 10-15 m
  2. Other Conversions
    • √2 = 1.4
    • √3 = 1.7
    • sin30 = 1/2
    • cos30 = √3/2 ~ .86
    • sin60 = √3/2
    • cos60 = 1/2
    • sin & cos 45 = √2/2 ~ .7
  3. Milligram Conversions
    1 mg = 10-3 g = 10-6 kg
  4. Distance
    • a Scalar quantity that refers to how much ground an object has covered during its motion
    • will only equal 0 if you don’t move at all
  5. Displacement
    • a Vector quantity that refers to how far out of place an object is from where it started, aka it’s the object's overall change in position
    • displacement is the quantity that can equal 0 when you end in the same place you started
  6. (average) Acceleration
    • change in velocity divided by the elapsed time for that change
    • a = v2 - v1 / Δt
    • aka change in velocity / elapsed time
  7. Most basic translational motion equation:
    • d = vt
    • distance (meters) = velocity (m/s) * time (s)
  8. What equation should be used if vf is missing?
    d = vot + 1/2at2
  9. What equation should be used if d is missing?
    vf = vo + at
  10. What equation should be used if t is missing?
    vf2 = vo2 + 2ad
  11. Equation to find the time at the top of a projectile motion problem?
    • ttop = voy/g
    • same thing as saying m/s * s2/m
  12. Equation to find the height at the top of a projectile motion problem?
    h = voy2 / 2g
  13. What equation can be used to determine an object’s displacement during FREE-FALL?
    • d (Δh) = 5t2
    • from d = vot + 1/2at2
  14. Objects with a ____ contact area-to-mass ratio experience a more significant impact of wind resistance than their denser counterparts.
    Objects with a LARGE surface area : mass ratio experience MORE wind resistance than their denser (therefore heavier) counterparts
  15. Terminal Velocity
    • vterm occurs when the drag Force upward is equal & opposite to the Force of gravity (Fg)

    • • the object with the greatest terminal velocity will be:
    • 1. the DENSEST

    2. have the LEAST amount of contact area
  16. Projectile Motion
    • vox = vocosθ
    • voy = vosinθ
  17. Range Equations (3)
    • r = vo2sin2θ / g
    • r = 2voxvoy / g
    • r45° = 4hmax
  18. Which launch angle results in the maximum range & which results in the maximum height?
    • a 45° launch angle corresponds to the maximum possible RANGE

    • a 90° launch angle corresponds to the maximum possible HEIGHT

    • 30° & 60° launch angles correspond to the same range

What would you like to do?

Home > Flashcards > Print Preview