Because equilibrium constant K is equal to k1/k-1, the forward rate constant is given by k1=K*k-1
In other words, the rate of proton diffusion does what?
However, if carbon dioxide is hydrated at a rate of 106
s-1, then every step in the mechanism must take place at least this fast
limits the rate of proton release to less than 104s-1 for a group with pKa=7.