Chem 112

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Author:
tessaj21
ID:
36897
Filename:
Chem 112
Updated:
2010-09-23 15:34:10
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Colligative 1st chem test
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Description:
Physical & Colligative properties E.G. Vapor pressure, boiling point, etc...
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  1. As temperature increases, solubility ______ for solids but _______ for gas.
    Increases, decreases
  2. A colligative property is a physical property that is dependent on ________ ?
    The # of solute particles but not their identity
  3. As # of particles increases, vapor pressure ______.
    Reduces
  4. As # of particles increases, freezing point _______.
    Decreases
  5. As # of particles increases, boiling point ______.
    Increases
  6. Vapor Pressure ________
    Reduction
  7. Boiling Point _______
    Elevation
  8. Freezing Point _______
    Depression
  9. What is the van't Hoff factor?
    i = the # of particles the substance breaks into
  10. As # of particles increase, osmosis pressure _______.
    Increases
  11. How many particles does 2m NaCl have?
    • 4
    • NaCl -> Na + Cl
    • 2 particles X 2m = 4
  12. How many particles does 2m CH3COOH have?
    • Weak electrolyte so partially dissociates into ions.
    • 1 < i < 2
    • 2-4 particles
  13. All non-electrolytes have what van't Hoff factor?
    i = 1
  14. In an equation, use the van't Hoff factor for the ______ & the constant for the ________.
    Solute, Solvent
  15. In an equation, when do u worry about the van't Hoff factor?
    When the solute is a strong or weak electrolyte
  16. How do u find the change in temperature of boiling point?
    Constant of solvent X van't Hoff factor (if necessary) X molality
  17. After finding the change of boiling temp, how do u find the temperature of the solution?
    • Take ur change in temp & add it to the boiling of solvent (in celsius)
    • E.G. Change in temp is .34 so add that to 100 (water's boiling point) = 100.34 C
  18. How do u find the temperature change in freezing point?
    Constant of freezing solvent X van't Hoff factor (if necessary) X molality
  19. After finding the change in freezing temp, how do u find the freezing point for the solution?
    • Subtract the change in freezing temp from the freezing point of the solvent.
    • E.G. Change in temp is 1.23 so subtract that from 0 (water's freezing point) =
    • -1.23 C
  20. What is Raoult's Law? (Vapor Pressure)
    • Pa = Xa (Pure a)
    • Solution's vapor pressure = mole fraction X pure solvent's vapor pressure

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