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lesson 1 and 2
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when can a limit fail to exist?
when the limit approaches a different number on both sides
how do you evaluate
lim (3x^2+4x-5)
x-2
plug in 2 where all the x's are
what do you do when substitution gives
k
___
0
the limit does not exist
what do you do when substitution gives you
0
___
0
you have to factor then plug in the limit
when the limit goes to infinity, and the degree of the top is smaller than the degree of the bottom then
its equal to 0
when the limit is infinity, and the degree of the top is same as the bottom then
make a fraction from the leading coefficients
when limit is infinity, and the degree of the top is greater than the bottom then
divide each term by the highest powerof x in the bottom and simplify
state the left & right hand limit
state the limit
left hand limit is 2
right hand limit is 1
the limit does not exist b/c they dont go to the same number
when they ask to find the continuity then
find the domain which means set it equal to 0
if its a quotient set the denominator equal to 0
steps to finding continuity at a point
see if f(a) is defined meaning when you plug in the point it equals a real #
then find the left and right hand limit
then see if f(x)=f(a) then its continuous
Author:
jillmray
ID:
68363
Card Set:
lesson 1 and 2
Updated:
2011-02-23 11:11:42
Tags:
business calulus
Folders:
Description:
limits and one sided limits
Show Answers:
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